CFVR1076 - EC3-05 test: Compression Buckling
Compression Buckling checking according to EN 1993-1-1:2005
A fixed steel beam subjected to a Fy load of -250 kN.
The beam has a length of 1 m.
The cross section is a HE 1000 x 415 .
The beam is made of Fe 460 steel which has a fy of 460000 kN/m2.
The aim of the example is to obtain the cross section classification and compression buckling criterion according to EN 1993-1-1:2005.
Element types used in the model: BEAM4 Needed CivilFEM Modules: |
|
| Model Statistics | |
| Number of elements | 1 |
| Number of nodes | 2 |
| Number of civil materials | 1 |
| Number of cross sections | 1 |
| Number of shell vertices | 0 |
Log file: CFVR1076.DAT
FINISH ~CFCLEAR,,1 NomFile='CFVR1076' /TITLE, %NomFile%, EC3-05 test: Compression Buckling ! --------------------------------------------------------------------------------- ! Model definition and solve ! --------------------------------------------------------------------------------- ! CivilFEM Setup: Code & Units ~UNITS,,LENG,M ~UNITS,,TIME,S ~UNITS,,FORC,KN ~CODESEL,EC3-05,EC2-08,,,EC8-94 /PREP7 ! Materials ~CFMP,1,LIB,STEEL,UNE,S 460 ! Element Types ET,1,BEAM4 ! Type 1: 3D Beam ! Cross Sections ~SSECLIB,1,1,9,11 !HE 1000 x 415 ! Member properties ! ~MEMBPRO,1,EC3,ALL, L, K, KW, C1, C2, C3, CMY, CMZ, CMLT,PSIVEC,LATB,CFBXY,CFBXZ,CHKAX ~MEMBPRO,1,EC3,ALL,10,1.000,1.000,1.000, 1.0, 1.0, 1.0, 1.0, 1.0, 0.5, 1, 1.0, 1.0, 0, ! Beam properties ~BMSHPRO,1,BEAM,1,,,,4,1,0,, ! Nodes N, 1 N,25,,10 ! FILL, 1,25 ! Elements ! E,1,2 ! EGEN,24,1,1 E,1,25 EPLOT /SOLU ! Displacements D, 1,UX D, 1,UY D, 1,UZ D,25,UX D,25,UZ D,ALL,ROTY ! Apply Load F,25,FY,-250 ! Solve SOLVE /POST1 ! Read results ~CFSET,,1,1 ! Read the first load step ! Buckling checking ~CHKSTL,BUCK_CMP,-Z,PARTIAL !-------------------------------------------------------------------------------------- ! DATA CHECK !-------------------------------------------------------------------------------------- ! Data comparison number NComp = 13 NComp_ch = 0 ! Matrix dim. *DIM,LABEL,CHAR,Ncomp,1 *DIM,LABEL_CH,CHAR,Ncomp_ch,1 *DIM,VALUE,,Ncomp,3 *DIM,VALUE_CH,CHAR,Ncomp_ch,3 *DIM,TOLER,,Ncomp,2 ! Labels !-------------------------------------------------------------------------------------- LABEL( 1,1) = 'CLASS' LABEL( 2,1) = 'ALP_Z' LABEL( 3,1) = 'AREA' LABEL( 4,1) = 'LAM_Y' LABEL( 5,1) = 'LAM_Z' LABEL( 6,1) = 'PHI_Y' LABEL( 7,1) = 'PHI_Z' LABEL( 8,1) = 'CHI_Y' LABEL( 9,1) = 'CHI_Z' LABEL(10,1) = 'NCR_Y' LABEL(11,1) = 'NCR_Z' LABEL(12,1) = 'NBRD' LABEL(13,1) = 'CRT_TOT' ! Correct values !-------------------------------------------------------------------------------------- VALUE( 1,1)= 4 VALUE( 2,1)= 0.49 VALUE( 3,1)= 0.050413 VALUE( 4,1)= 0.341904 VALUE( 5,1)= 2.1433 VALUE( 6,1)= 0.5826 VALUE( 7,1)= 3.273 VALUE( 8,1)= 0.94853 VALUE( 9,1)= 0.1740235 VALUE(10,1)= 176814.9498 VALUE(11,1)= 4499.651343 VALUE(12,1)= 3271.62 VALUE(13,1)= 0.0765 ! Obtained values !-------------------------------------------------------------------------------------- ~PLLSSTL,CLASS *GET,VALUE( 1,2),ELEM,1,ETAB,CLASS_J ~PLLSSTL,ALP_Z *GET,VALUE( 2,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,AREA *GET,VALUE( 3,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,LAM_Y *GET,VALUE( 4,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,LAM_Z *GET,VALUE( 5,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,PHI_Y *GET,VALUE( 6,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,PHI_Z *GET,VALUE( 7,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,CHI_Y *GET,VALUE( 8,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,CHI_Z *GET,VALUE( 9,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,NCR_Y *GET,VALUE(10,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,NCR_Z *GET,VALUE(11,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,NBRD *GET,VALUE(12,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,CRT_TOT *GET,VALUE(13,2),ELEM,1,ETAB,CFETAB_J ! Warning and error tolerances TOLER( 1,1)= 0 $ TOLER( 1,2)= 0 TOLER( 2,1)= 1E-2 $ TOLER( 2,2)= 1E-2 TOLER( 3,1)= 1E-4 $ TOLER( 3,2)= 1E-4 TOLER( 4,1)= 1E-3 $ TOLER( 4,2)= 1E-3 TOLER( 5,1)= 1E-2 $ TOLER( 5,2)= 1E-2 TOLER( 6,1)= 1E-2 $ TOLER( 6,2)= 1E-2 TOLER( 7,1)= 1E-1 $ TOLER( 7,2)= 1E-1 TOLER( 8,1)= 1E-2 $ TOLER( 8,2)= 1E-2 TOLER( 9,1)= 1E-2 $ TOLER( 9,2)= 1E-2 TOLER(10,1)= 1E+1 $ TOLER(10,2)= 1E+1 TOLER(11,1)= 1E+1 $ TOLER(11,2)= 1E+1 TOLER(12,1)= 1E-0 $ TOLER(12,2)= 1E-0 TOLER(13,1)= 1E-2 $ TOLER(13,2)= 1E-2 !-------------------------------------------------------------------------------------- ! Results comparison !-------------------------------------------------------------------------------------- COMPARA.MAC |
Results
| Label | Target | CivilFEM | Ratio | Tolerance |
| CLASS | 4 | 4 | 1.000 | 0 |
| ALP_Z | 0.49 | 0.49 | 1.000 | 0.01 |
| AREA | 0.050413 | 0.050404 | 1.000 | 0.0001 |
| LAM_Y | 0.3419 | 0.34187 | 1.000 | 0.001 |
| LAM_Z | 2.1433 | 2.1424 | 1.000 | 0.01 |
| PHI_Y | 0.5826 | 0.58255 | 1.000 | 0.01 |
| PHI_Z | 3.273 | 3.2708 | 1.001 | 0.1 |
| CHI_Y | 0.94853 | 0.94854 | 1.000 | 0.01 |
| CHI_Z | 0.17402 | 0.17414 | 0.999 | 0.01 |
| NCR_Y | 1.7681e+005 | 1.7682e+005 | 1.000 | 10 |
| NCR_Z | 4499.7 | 4502.4 | 0.999 | 10 |
| NBRD | 3271.6 | 3271.6 | 1.000 | 1 |
| CRT_TOT | 0.0765 | 0.076415 | 1.001 | 0.01 |
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