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CFVR1253 - Torsion checking according to ITER Structural Design Code for Buildings

Check a reinforced concrete beam subjected to torsional moment according to ITER Structural Design Code for Buildings

A fixed beam with a rectangular reinforced concrete section is subjected to a uniform distributed load of 7.52 Mp and a torsional moment of 1.52 Mp*m.
The aim of the example is to obtain the check criterion according to ITER Structural Design Code for Buildings.

Element types used in the model: BEAM4

Needed CivilFEM Modules:
Geotechnical Module
Bridges and Civil Non Linearities Module
Advanced Prestressed Concrete Module

The example can be launched on an educational license.
KEYWORDS
Beam
Cross Section
Code Checking/Design
Reinforced Concrete
ITER

Model Statistics
Number of elements 4
Number of nodes 5
Number of civil materials 2
Number of cross sections 1
Number of shell vertices 0

Log file: CFVR1253.DAT


   FINISH
  ~CFCLEAR,,1
   NomFile='CFVR1253'
  /TITLE,%NomFile%, Torsion checking according to ITER Structural Design Code for Buildings

! -------------------------------------------------------------------------------------
! Initial data
! -------------------------------------------------------------------------------------
! CivilFEM SETUP
  ~UNITS,,LENG,M
  ~UNITS,,TIME,S
  ~UNITS,,FORC,MP
  ~CODESEL,EC3-92,ITER,EC2-08,,EC8-04

! Preprocessor
  /PREP7

! Parameters
  L=1              ! Length in m
  b=.4             ! Cross-section width in m.
  h=.3             ! Depth in m.
  T=0.95*1.6       ! Torsional moment in Mp*m
  Q=4.7*1.6        ! Maximum concomitant design shear force in Mp

! Material Definition
 ~CFMP,1,LIB,CONCRETE,EC2,C25/30
 ~CFMP,2,LIB,REINF,EC2,S400

! Element Type Definition
  ET,1,Beam4                                 ! Element Type 1: 3D Beam

! Cross-section definition
 ~CSECDMS,1,REC,1,0.3,0.4
! Reinforcement definition
 ~RNFDEF,1,TORSION,2,3.03e-4,,,,3.27e-4,     ! Torsional reinforcement
! Beam properties
 ~BMSHPRO,1,BEAM,1,1,,,4,1,0,,

! Model Construction
  N,1                                    ! Nodes input
  N,5,L
  FILL,1,5

  E,1,2                                  ! Elements input
  EGEN,4,1,1,1

  D,1, , , , , ,ALL                      ! Constraint conditions

/SOLU
  F,5,FY,-Q
  F,5,MX,T
  SOLVE               ! Calculation

/POST1
! Postprocessor
  ~CFSET,,1,1       ! Read first load step

! Torsion checking
  ~CHKCON,SHT,TORSION

!--------------------------------------------------------------------------------------
! DATA CHECK
!--------------------------------------------------------------------------------------
! Data comparison number
  NComp = 5
  NComp_ch = 0

! Matrix dim.
  *DIM,LABEL,CHAR,Ncomp,1
  *DIM,LABEL_CH,CHAR,Ncomp_ch,1
  *DIM,VALUE,,Ncomp,3
  *DIM,VALUE_CH,CHAR,Ncomp_ch,3
  *DIM,TOLER,,Ncomp,2

! Labels
  LABEL(1,1) = 'TRDMAX'
  LABEL(2,1) = 'TRD'
  LABEL(3,1) = 'CRT2'
  LABEL(4,1) = 'CRTALT'
  LABEL(5,1) = 'CRT_TOT'

! Correct values
  VALUE(1,1)=5.8844
  VALUE(2,1)=1.447
  VALUE(3,1)=1.0504
  VALUE(4,1)=1.0287
  VALUE(5,1)=1.0504

! Comparison
 ~PLLSCON,TRDMAX
 *GET,VALUE(1,2),ELEM,1,ETAB,CFETAB_I
 ~PLLSCON,TRD
  *GET,VALUE(2,2),ELEM,1,ETAB,CFETAB_I
 ~PLLSCON,CRT_2
  *GET,VALUE(3,2),ELEM,1,ETAB,CFETAB_I
 ~PLLSCON,CRTALT
  *GET,VALUE(4,2),ELEM,1,ETAB,CFETAB_I
 ~PLLSCON,CRT_TOT
  *GET,VALUE(5,2),ELEM,1,ETAB,CFETAB_I

! Warning and error tolerances
  TOLER( 1, 1)= 1E-02 $ TOLER( 1, 2)= 1E-02
  TOLER( 2, 1)= 1E-02 $ TOLER( 2, 2)= 1E-02
  TOLER( 3, 1)= 1E-03 $ TOLER( 3, 2)= 1E-03
  TOLER( 4, 1)= 1E-03 $ TOLER( 4, 2)= 1E-03
  TOLER( 5, 1)= 1E-03 $ TOLER( 5, 2)= 1E-03

!--------------------------------------------------------------------------------------
! Results comparison
!--------------------------------------------------------------------------------------
  COMPARA.MAC

Results

LabelTargetCivilFEMRatioTolerance
TRDMAX 5.8844 5.88641.000 0.01
TRD 1.447 1.44751.000 0.01
CRT2 1.0504 1.05011.000 0.001
CRTALT 1.0287 1.02861.000 0.001
CRT_TOT 1.0504 1.05011.000 0.001


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