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CFVR7211 - Bending + Axial force design according to ACI 349

Design a reinforced concrete beam subjected to Bending + Axial force according to ACI 349

A fixed beam which has a rectangular reinforced concrete section is subjected to an axial compression force of 500 kips and a bending moment of 245 ft-kips.
The aim of the example is to obtain the necessary steel amount according to ACI 349.

Element types used in the model: BEAM4

Needed CivilFEM Modules:
Geotechnical Module
Bridges and Civil Non Linearities Module
Advanced Prestressed Concrete Module

The example can be launched on an educational license.
KEYWORDS
Beam
Cross Section
Code Checking/Design
Reinforced Concrete
ACI 349

Model Statistics
Number of elements 4
Number of nodes 5
Number of civil materials 2
Number of cross sections 1
Number of shell vertices 0

Log file: CFVR7211.DAT


   FINISH
  ~CFCLEAR,,1
   NomFile='CFVR7211'
 /TITLE,%NomFile%, BENDING + AXIAL FORCE DESIGN ACCORDING TO ACI 349
! --------------------------------------------------------------------
! Initial data
! --------------------------------------------------------------------
! CivilFEM SETUP
 ~CFACTIV,NUCL,Y
 ~UNITS,BIN    ! in, sg, Pound force
 ~CODESEL,EC3-92,ACI349,,,EC8-94

! Preprocessor
  /PREP7

! Material Definition
 ~CFMP,1,LIB,CONCRETE,ACI,fc_5000
 ~CFMP,2,LIB,REINF,ACI,fy_60000

! Element Type Definition
  ET,1,Beam4                            ! Element Type 1: 3D Beam

! Cross-section definition
 ~CSECDMS,1,REC,1,18,18
! Reinforcement definition
 ~RNFDEF,1,1,2,2,0,1.87,1.0  ! Top Reinf.: Total A.: 1 in^2, Mech. cover:1.87 in
 ~RNFDEF,1,2,2,4,0,1.87,1.0  ! Bot Reinf.: Total A.: 1 in^2


! Beam & Shell property
 ~BMSHPRO,1,BEAM,1,1,,,4,1,,,Beam property

! Model Construction
  N,1                                   ! Nodes input
  N,5,200
  FILL,1,5
  E,1,2                                 ! Elements input
  EGEN,4,1,1,1
  D,1,ALL                               ! Boundary conditions

/SOLU
  M=2940000           ! 245 FT-KIPS bending moment
  H=-500000           ! 500 kips axial compression force
  F,5,FX,H
  F,5,MZ,M
  SOLVE               ! Calculation

/POST1

! Postprocessor
  ~CFSET,,1,1       ! Read first load step

! Bending + Axial design
  ~DIMCON,2DB,,0,1,5

!--------------------------------------------------------------------------------------
! DATA CHECK
!--------------------------------------------------------------------------------------
! Data comparison number
  NComp = 2
  NComp_ch = 0

! Matrix dim.
  *DIM,LABEL,CHAR,Ncomp,1
  *DIM,LABEL_CH,CHAR,Ncomp_ch,1
  *DIM,VALUE,,Ncomp,3
  *DIM,VALUE_CH,CHAR,Ncomp_ch,3
  *DIM,TOLER,,Ncomp,2

! Labels
  LABEL(1,1) = 'CRTC2D_I'
  LABEL(2,1) = 'CRTC2D_J'

! Correct values
  VALUE(1,1)=1.00
  VALUE(2,1)=1.817

! Comparison
 ~PLLSCON,CRT_TOT
 *GET,VALUE(1,2),ELEM,4,ETAB,CFETAB_I
 ~PLLSCON,REINFACT
 *GET,VALUE(2,2),ELEM,4,ETAB,CFETAB_J

! Warning and error tolerances
  TOLER( 1, 1)= 3E-02 $ TOLER( 1, 2)= 5E-02
  TOLER( 2, 1)= 2E-01 $ TOLER( 2, 2)= 2E-01

!--------------------------------------------------------------------------------------
! Results comparison
!--------------------------------------------------------------------------------------
  COMPARA.MAC

Results

LabelTargetCivilFEMRatioTolerance
CRTC2D_I 1 11.000 0.05
CRTC2D_J 1.817 1.86820.972 0.2


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